Optimal. Leaf size=107 \[ -\frac {b \left (a+b \tanh ^{-1}(c x)\right )}{c d^2 (c x+1)}-\frac {\left (a+b \tanh ^{-1}(c x)\right )^2}{c d^2 (c x+1)}+\frac {\left (a+b \tanh ^{-1}(c x)\right )^2}{2 c d^2}-\frac {b^2}{2 c d^2 (c x+1)}+\frac {b^2 \tanh ^{-1}(c x)}{2 c d^2} \]
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Rubi [A] time = 0.12, antiderivative size = 107, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 6, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.316, Rules used = {5928, 5926, 627, 44, 207, 5948} \[ -\frac {b \left (a+b \tanh ^{-1}(c x)\right )}{c d^2 (c x+1)}-\frac {\left (a+b \tanh ^{-1}(c x)\right )^2}{c d^2 (c x+1)}+\frac {\left (a+b \tanh ^{-1}(c x)\right )^2}{2 c d^2}-\frac {b^2}{2 c d^2 (c x+1)}+\frac {b^2 \tanh ^{-1}(c x)}{2 c d^2} \]
Antiderivative was successfully verified.
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Rule 44
Rule 207
Rule 627
Rule 5926
Rule 5928
Rule 5948
Rubi steps
\begin {align*} \int \frac {\left (a+b \tanh ^{-1}(c x)\right )^2}{(d+c d x)^2} \, dx &=-\frac {\left (a+b \tanh ^{-1}(c x)\right )^2}{c d^2 (1+c x)}+\frac {(2 b) \int \left (\frac {a+b \tanh ^{-1}(c x)}{2 d (1+c x)^2}-\frac {a+b \tanh ^{-1}(c x)}{2 d \left (-1+c^2 x^2\right )}\right ) \, dx}{d}\\ &=-\frac {\left (a+b \tanh ^{-1}(c x)\right )^2}{c d^2 (1+c x)}+\frac {b \int \frac {a+b \tanh ^{-1}(c x)}{(1+c x)^2} \, dx}{d^2}-\frac {b \int \frac {a+b \tanh ^{-1}(c x)}{-1+c^2 x^2} \, dx}{d^2}\\ &=-\frac {b \left (a+b \tanh ^{-1}(c x)\right )}{c d^2 (1+c x)}+\frac {\left (a+b \tanh ^{-1}(c x)\right )^2}{2 c d^2}-\frac {\left (a+b \tanh ^{-1}(c x)\right )^2}{c d^2 (1+c x)}+\frac {b^2 \int \frac {1}{(1+c x) \left (1-c^2 x^2\right )} \, dx}{d^2}\\ &=-\frac {b \left (a+b \tanh ^{-1}(c x)\right )}{c d^2 (1+c x)}+\frac {\left (a+b \tanh ^{-1}(c x)\right )^2}{2 c d^2}-\frac {\left (a+b \tanh ^{-1}(c x)\right )^2}{c d^2 (1+c x)}+\frac {b^2 \int \frac {1}{(1-c x) (1+c x)^2} \, dx}{d^2}\\ &=-\frac {b \left (a+b \tanh ^{-1}(c x)\right )}{c d^2 (1+c x)}+\frac {\left (a+b \tanh ^{-1}(c x)\right )^2}{2 c d^2}-\frac {\left (a+b \tanh ^{-1}(c x)\right )^2}{c d^2 (1+c x)}+\frac {b^2 \int \left (\frac {1}{2 (1+c x)^2}-\frac {1}{2 \left (-1+c^2 x^2\right )}\right ) \, dx}{d^2}\\ &=-\frac {b^2}{2 c d^2 (1+c x)}-\frac {b \left (a+b \tanh ^{-1}(c x)\right )}{c d^2 (1+c x)}+\frac {\left (a+b \tanh ^{-1}(c x)\right )^2}{2 c d^2}-\frac {\left (a+b \tanh ^{-1}(c x)\right )^2}{c d^2 (1+c x)}-\frac {b^2 \int \frac {1}{-1+c^2 x^2} \, dx}{2 d^2}\\ &=-\frac {b^2}{2 c d^2 (1+c x)}+\frac {b^2 \tanh ^{-1}(c x)}{2 c d^2}-\frac {b \left (a+b \tanh ^{-1}(c x)\right )}{c d^2 (1+c x)}+\frac {\left (a+b \tanh ^{-1}(c x)\right )^2}{2 c d^2}-\frac {\left (a+b \tanh ^{-1}(c x)\right )^2}{c d^2 (1+c x)}\\ \end {align*}
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Mathematica [A] time = 0.14, size = 124, normalized size = 1.16 \[ \frac {-4 a^2+2 a b \log (c x+1)+2 a b c x \log (c x+1)-b (2 a+b) (c x+1) \log (1-c x)-4 b (2 a+b) \tanh ^{-1}(c x)-4 a b+b^2 \log (c x+1)+b^2 c x \log (c x+1)+2 b^2 (c x-1) \tanh ^{-1}(c x)^2-2 b^2}{4 c d^2 (c x+1)} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.46, size = 101, normalized size = 0.94 \[ \frac {{\left (b^{2} c x - b^{2}\right )} \log \left (-\frac {c x + 1}{c x - 1}\right )^{2} - 8 \, a^{2} - 8 \, a b - 4 \, b^{2} + 2 \, {\left ({\left (2 \, a b + b^{2}\right )} c x - 2 \, a b - b^{2}\right )} \log \left (-\frac {c x + 1}{c x - 1}\right )}{8 \, {\left (c^{2} d^{2} x + c d^{2}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.16, size = 119, normalized size = 1.11 \[ \frac {1}{8} \, c {\left (\frac {{\left (c x - 1\right )} b^{2} \log \left (-\frac {c x + 1}{c x - 1}\right )^{2}}{{\left (c x + 1\right )} c^{2} d^{2}} + \frac {2 \, {\left (2 \, a b + b^{2}\right )} {\left (c x - 1\right )} \log \left (-\frac {c x + 1}{c x - 1}\right )}{{\left (c x + 1\right )} c^{2} d^{2}} + \frac {2 \, {\left (2 \, a^{2} + 2 \, a b + b^{2}\right )} {\left (c x - 1\right )}}{{\left (c x + 1\right )} c^{2} d^{2}}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.06, size = 341, normalized size = 3.19 \[ -\frac {a^{2}}{c \,d^{2} \left (c x +1\right )}-\frac {b^{2} \arctanh \left (c x \right )^{2}}{c \,d^{2} \left (c x +1\right )}-\frac {b^{2} \arctanh \left (c x \right ) \ln \left (c x -1\right )}{2 c \,d^{2}}-\frac {b^{2} \arctanh \left (c x \right )}{c \,d^{2} \left (c x +1\right )}+\frac {b^{2} \arctanh \left (c x \right ) \ln \left (c x +1\right )}{2 c \,d^{2}}-\frac {b^{2} \ln \left (c x -1\right )^{2}}{8 c \,d^{2}}+\frac {b^{2} \ln \left (c x -1\right ) \ln \left (\frac {1}{2}+\frac {c x}{2}\right )}{4 c \,d^{2}}-\frac {b^{2} \ln \left (c x -1\right )}{4 c \,d^{2}}-\frac {b^{2}}{2 c \,d^{2} \left (c x +1\right )}+\frac {b^{2} \ln \left (c x +1\right )}{4 c \,d^{2}}-\frac {b^{2} \ln \left (c x +1\right )^{2}}{8 c \,d^{2}}+\frac {b^{2} \ln \left (-\frac {c x}{2}+\frac {1}{2}\right ) \ln \left (c x +1\right )}{4 c \,d^{2}}-\frac {b^{2} \ln \left (-\frac {c x}{2}+\frac {1}{2}\right ) \ln \left (\frac {1}{2}+\frac {c x}{2}\right )}{4 c \,d^{2}}-\frac {2 a b \arctanh \left (c x \right )}{c \,d^{2} \left (c x +1\right )}-\frac {a b \ln \left (c x -1\right )}{2 c \,d^{2}}-\frac {a b}{c \,d^{2} \left (c x +1\right )}+\frac {a b \ln \left (c x +1\right )}{2 c \,d^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.33, size = 277, normalized size = 2.59 \[ -\frac {1}{2} \, {\left (c {\left (\frac {2}{c^{3} d^{2} x + c^{2} d^{2}} - \frac {\log \left (c x + 1\right )}{c^{2} d^{2}} + \frac {\log \left (c x - 1\right )}{c^{2} d^{2}}\right )} + \frac {4 \, \operatorname {artanh}\left (c x\right )}{c^{2} d^{2} x + c d^{2}}\right )} a b - \frac {1}{8} \, {\left (4 \, c {\left (\frac {2}{c^{3} d^{2} x + c^{2} d^{2}} - \frac {\log \left (c x + 1\right )}{c^{2} d^{2}} + \frac {\log \left (c x - 1\right )}{c^{2} d^{2}}\right )} \operatorname {artanh}\left (c x\right ) + \frac {{\left ({\left (c x + 1\right )} \log \left (c x + 1\right )^{2} + {\left (c x + 1\right )} \log \left (c x - 1\right )^{2} - 2 \, {\left (c x + {\left (c x + 1\right )} \log \left (c x - 1\right ) + 1\right )} \log \left (c x + 1\right ) + 2 \, {\left (c x + 1\right )} \log \left (c x - 1\right ) + 4\right )} c^{2}}{c^{4} d^{2} x + c^{3} d^{2}}\right )} b^{2} - \frac {b^{2} \operatorname {artanh}\left (c x\right )^{2}}{c^{2} d^{2} x + c d^{2}} - \frac {a^{2}}{c^{2} d^{2} x + c d^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.25, size = 97, normalized size = 0.91 \[ \frac {b^2\,{\mathrm {atanh}\left (c\,x\right )}^2+b^2\,\mathrm {atanh}\left (c\,x\right )+2\,a\,b\,\mathrm {atanh}\left (c\,x\right )}{2\,c\,d^2}-\frac {2\,a^2+4\,a\,b\,\mathrm {atanh}\left (c\,x\right )+2\,a\,b+2\,b^2\,{\mathrm {atanh}\left (c\,x\right )}^2+2\,b^2\,\mathrm {atanh}\left (c\,x\right )+b^2}{2\,x\,c^2\,d^2+2\,c\,d^2} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {\int \frac {a^{2}}{c^{2} x^{2} + 2 c x + 1}\, dx + \int \frac {b^{2} \operatorname {atanh}^{2}{\left (c x \right )}}{c^{2} x^{2} + 2 c x + 1}\, dx + \int \frac {2 a b \operatorname {atanh}{\left (c x \right )}}{c^{2} x^{2} + 2 c x + 1}\, dx}{d^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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